document.write( "Question 144633This question is from textbook Basic Technical Mathematics with Calculus
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document.write( ": A developer purchased 70 acres of land for $900,000. If part cost $20,000 per acre and the remainder cost $10,000 per acre, how many acres did the developer buy at each price? \n" );
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Algebra.Com's Answer #105384 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 20,000x+10,000(70-x)=900,000 \n" ); document.write( "20,000x+700,000-10,000x=900,000 \n" ); document.write( "10,000x=900,000-700,000 \n" ); document.write( "10,000x=200,000 \n" ); document.write( "x=200,000/10,000 \n" ); document.write( "x=20 acres were bought for $20,000 per acre. \n" ); document.write( "70-20=50 acres were bought for $10,000 per acre. \n" ); document.write( "proof: \n" ); document.write( "20,000*20+10,000*50=900,000 \n" ); document.write( "400,000+500,000=900,000 \n" ); document.write( "900,000=900,000 \n" ); document.write( " |