document.write( "Question 144613: Jane invested some amount at the rate of 12% simple interest and some other amount at the rate of 10% simple interest. She received yearly interest of $130. Randy also invested in the same scheme, but he interchanged the amounts invested, and received $4 more as interest. How much amount did each of them invest at different rates?
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #105379 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Jane invested some amount at the rate of 12% simple interest and some other amount at the rate of 10% simple interest. She received yearly interest of $130. Randy also invested in the same scheme, but he interchanged the amounts invested, and received $4 more as interest. How much amount did each of them invest at different rates? \n" ); document.write( ": \n" ); document.write( "Let x = amt J invested at 12% \n" ); document.write( "Let y = amt J invested at 10% \n" ); document.write( "J's total interest = $130 \n" ); document.write( "Also \n" ); document.write( "x = amt R invested at 10% \n" ); document.write( "y = amt R invested at 12% \n" ); document.write( "R's total interest = $134 \n" ); document.write( ": \n" ); document.write( "Two equations \n" ); document.write( ".12x + .10y = 130 (J's investments) \n" ); document.write( ".10x + .12y = 134 (R's investments) \n" ); document.write( ": \n" ); document.write( "Multiply the 1st equation by 1.2 and subtract the 2nd equation, find x \n" ); document.write( ".144x + .12y = 156 \n" ); document.write( ".10x + .12y = 134 \n" ); document.write( "---------------------subtracting eliminates y \n" ); document.write( ".044x = 22 \n" ); document.write( "x = \n" ); document.write( "x = $500; J has invested at 12% and R has invested at 10% \n" ); document.write( ": \n" ); document.write( "Find y using (.12x + .10y = 130) \n" ); document.write( ".12(500) + .10y = 130 \n" ); document.write( "60 = .10y = 130 \n" ); document.write( ".10y = 130 - 60 \n" ); document.write( ".1y = 70 \n" ); document.write( "y = \n" ); document.write( "y = $700; J has invested at 10% and R has invested at 12% \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution using (.10x + .12y = 134) \n" ); document.write( ".10(500) + .12(700) = \n" ); document.write( "50 + 84 = 134; confirms our solutions \n" ); document.write( " |