document.write( "Question 144613: Jane invested some amount at the rate of 12% simple interest and some other amount at the rate of 10% simple interest. She received yearly interest of $130. Randy also invested in the same scheme, but he interchanged the amounts invested, and received $4 more as interest. How much amount did each of them invest at different rates?
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Algebra.Com's Answer #105379 by ankor@dixie-net.com(22740)\"\" \"About 
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Jane invested some amount at the rate of 12% simple interest and some other amount at the rate of 10% simple interest. She received yearly interest of $130. Randy also invested in the same scheme, but he interchanged the amounts invested, and received $4 more as interest. How much amount did each of them invest at different rates?
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\n" ); document.write( "Let x = amt J invested at 12%
\n" ); document.write( "Let y = amt J invested at 10%
\n" ); document.write( "J's total interest = $130
\n" ); document.write( "Also
\n" ); document.write( "x = amt R invested at 10%
\n" ); document.write( "y = amt R invested at 12%
\n" ); document.write( "R's total interest = $134
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\n" ); document.write( "Two equations
\n" ); document.write( ".12x + .10y = 130 (J's investments)
\n" ); document.write( ".10x + .12y = 134 (R's investments)
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\n" ); document.write( "Multiply the 1st equation by 1.2 and subtract the 2nd equation, find x
\n" ); document.write( ".144x + .12y = 156
\n" ); document.write( ".10x + .12y = 134
\n" ); document.write( "---------------------subtracting eliminates y
\n" ); document.write( ".044x = 22
\n" ); document.write( "x = \"22%2F.044\"
\n" ); document.write( "x = $500; J has invested at 12% and R has invested at 10%
\n" ); document.write( ":
\n" ); document.write( "Find y using (.12x + .10y = 130)
\n" ); document.write( ".12(500) + .10y = 130
\n" ); document.write( "60 = .10y = 130
\n" ); document.write( ".10y = 130 - 60
\n" ); document.write( ".1y = 70
\n" ); document.write( "y = \"70%2F.1\"
\n" ); document.write( "y = $700; J has invested at 10% and R has invested at 12%
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\n" ); document.write( "Check solution using (.10x + .12y = 134)
\n" ); document.write( ".10(500) + .12(700) =
\n" ); document.write( "50 + 84 = 134; confirms our solutions
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