document.write( "Question 144422: Tutors I submitted this once showing my work but I can't find my notes. If you sear your email you will see how I worked the problem. I asked if you could check my work. Here is the word problem again..Thank you $5000 is invested at interest rate K, compounded continuously and grows to $6954.84 in 6 years. Find the interest rate; the exponential growth function; the balance after 10 years and find the doubling time. \r
\n" ); document.write( "\n" ); document.write( "If I remember my notes I think I had the doubling time as 12 years, the interest rate at 6%.\r
\n" ); document.write( "\n" ); document.write( "Thank you
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Algebra.Com's Answer #105358 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
$5000 is invested at interest rate K, compounded continuously and grows to $6954.84 in 6 years. Find the interest rate; the exponential growth function; the balance after 10 years and find the doubling time.
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\n" ); document.write( "P*e^rt = A
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\n" ); document.write( "5000*e^6r = 6954.84
\n" ); document.write( "e^6r = \"6954.84%2F5000\"
\n" ); document.write( "Divide both sides by 5000
\n" ); document.write( "e^6r = 1.390968
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\n" ); document.write( "Find the nat log of both sides:
\n" ); document.write( "ln(e^6r) = 1.390968
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\n" ); document.write( "log equiv of exponents
\n" ); document.write( "6r*ln(e) = ln(1.390698)
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\n" ); document.write( "Find the ln of both sides (ln(e) = 1)
\n" ); document.write( "6r = .33000
\n" ); document.write( "r = \".33%2F6\"
\n" ); document.write( "r = .055, 5.5%
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\n" ); document.write( "Growth function
\n" ); document.write( "f(t) = 5000*e^.055t
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\n" ); document.write( "use this to check above solution on a calc: enter: 5000*e^(.055*6) = 6954.84
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\n" ); document.write( ":
\n" ); document.write( "the balance after 10 years
\n" ); document.write( "A = 5000*e^(.055*10)
\n" ); document.write( "A = 8666.26
\n" ); document.write( ":
\n" ); document.write( " and find the doubling time.
\n" ); document.write( "1*e^.055t = 2
\n" ); document.write( ".055t*ln(e) = ln(2)
\n" ); document.write( ".055t = .693147
\n" ); document.write( "t = \".693147%2F.055\"
\n" ); document.write( "t = 12.6 yrs
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\n" ); document.write( "Check this using the value of 5000 on calc: enter 5000*e^(.055*12.6) = 9998.53 ~ 10000
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