document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=144580>Question 144580</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The Hudson River flows at a rate of 3 miles per hour.  A patrol boat travels 60 miles upriver, and returns in a total time of 9 hours.  What is the speed of the boat in still water? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #105355 by </B><A HREF=/tutors/aboutme.mpl?userid=shahid><B>shahid(44)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=shahid><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=105355\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x mph be the speed of the boat in still water then<BR>\n" );
document.write( "(x+3)mph will be the speed of boat downstream<BR>\n" );
document.write( "(x-3)mph will be its speed in upstream<BR>\n" );
document.write( "now time taken by baot upstream t1=60/(x-3) and time taken by boat in downnstream t2=60/(x+3)<BR>\n" );
document.write( "t1+t2=9<BR>\n" );
document.write( "60/(x-3)+60/(x+3)=9<BR>\n" );
document.write( "60{1/(x-3)+1/(x+3)}=9<BR>\n" );
document.write( "x+3+x-3/x^2-9=9/60    taking LCM and dividing by 60 <BR>\n" );
document.write( "2x/x^2-9=3/20<BR>\n" );
document.write( "20(2x)=3(x^2-9)<BR>\n" );
document.write( "40x=3x^2-18<BR>\n" );
document.write( "3x^2-40x-18=0 solve this equation to get your answer </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );