document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=144606>Question 144606</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 54cm. Two times the height is 3cm more than the width. Find the length of the height and the length of the width.\r<BR>\n" );
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document.write( "this is the way i've been trying to solve this problem: P=2l+2w, right?<BR>\n" );
document.write( "we have the perimeter. 54=(2L+3)+2W. Is this right? I'm stuck! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #105350 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=105350\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 54 = 2H+2W (Height and Width) Length would work the same, but it says height.<BR>\n" );
document.write( "2H = W+3, so W = 2H - 3\r<BR>\n" );
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document.write( "Sub for W\r<BR>\n" );
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document.write( "54 = 2H + 2(2H-3)<BR>\n" );
document.write( "54 = 2H + 4H - 6<BR>\n" );
document.write( "60 = 6H<BR>\n" );
document.write( "H = 10<BR>\n" );
document.write( "W = 17<BR>\n" );
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