document.write( "Question 144606: The perimeter of a rectangle is 54cm. Two times the height is 3cm more than the width. Find the length of the height and the length of the width.\r
\n" ); document.write( "\n" ); document.write( "this is the way i've been trying to solve this problem: P=2l+2w, right?
\n" ); document.write( "we have the perimeter. 54=(2L+3)+2W. Is this right? I'm stuck! \n" ); document.write( "
Algebra.Com's Answer #105348 by ankor@dixie-net.com(22740)\"\" \"About 
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The perimeter of a rectangle is 54cm. Two times the height is 3cm more than the width. Find the length of the height and the length of the width.
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\n" ); document.write( "Let x = the width
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\n" ); document.write( "It says,\"Two times the height is 3cm more than the width.\" so we can say:
\n" ); document.write( "2h = (x + 3}
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\n" ); document.write( "Given perimeter:
\n" ); document.write( "2h + 2w = 54
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\n" ); document.write( "Substitute (x+3) for 2h and x for w and we have:
\n" ); document.write( "(x+3) + 2x = 54
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\n" ); document.write( "3x = 54 - 3
\n" ); document.write( "x = \"51%2F3\"
\n" ); document.write( "x = 17 cm is the width.
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\n" ); document.write( "Find the length from the equation 2h = (x+3)
\n" ); document.write( "2h = 17 + 3
\n" ); document.write( "2h = 20
\n" ); document.write( "h = 10 cm
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\n" ); document.write( "Check solution by finding the perimeter using these values \n" ); document.write( "
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