document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=143695>Question 143695</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of the number and its square root is 6/25,then find the number ?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #105310 by </B><A HREF=/tutors/aboutme.mpl?userid=shahid><B>shahid(44)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=shahid><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=105310\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let require number be x then following the conditions we get an equation<BR>\n" );
document.write( "x+sqrt(x)=6/25   now substitute sqrt(x)=y<BR>\n" );
document.write( "                         then        x =y^2  by squaring both sides<BR>\n" );
document.write( "y^2+y=6/25<BR>\n" );
document.write( "25y^2+25y=6  25 is multiplied on L.H.S<BR>\n" );
document.write( "25y^2+25y-6=0<BR>\n" );
document.write( "25y^2+30y-5y-6=0 <BR>\n" );
document.write( "5y(5y+6)-1(5y+6)=0<BR>\n" );
document.write( " (5y+6)(5y-1)=0<BR>\n" );
document.write( "either 5y+6=0 or 5y-1=0<BR>\n" );
document.write( "       5y=-6     5y=1<BR>\n" );
document.write( "        y=-6/5    y=1/5<BR>\n" );
document.write( "but from our substitution x=y^2<BR>\n" );
document.write( "either x=(-6/5)^2 or x=(1/5)^2<BR>\n" );
document.write( "       x=36/25   or  x=1/25   hope this is helpful fo you. </SPAN>\n" );
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