document.write( "Question 144375: irma is going to make three investments paying 8%, 9%, and 10%. She will invest twice as much at 9% as at 8% and $1000 more at 10%. if the yearly interest from the three investments is $3090 how much is invested altogether? \n" ); document.write( "
Algebra.Com's Answer #105309 by checkley77(12844) ![]() You can put this solution on YOUR website! .08x+.09*2x+.10(x+1000)=3090 \n" ); document.write( ".08x+.18x+.10x+100=3090 \n" ); document.write( ".36x=3090-100 \n" ); document.write( ".36x=2990 \n" ); document.write( "x=2990/.36 \n" ); document.write( "x=$8305.56 amount invsted @ 8% \n" ); document.write( "2*8305.56=16,611.11 invested @ 9% \n" ); document.write( "9305.56+1000=90305.56 invested @ 10% \n" ); document.write( "proof: \n" ); document.write( ".08*8302.56+.09*16611.11+.10*9305.56=3090 \n" ); document.write( "664.20+1495+930.56=3090 \n" ); document.write( "3090~3090 \n" ); document.write( " \n" ); document.write( " |