document.write( "Question 144375: irma is going to make three investments paying 8%, 9%, and 10%. She will invest twice as much at 9% as at 8% and $1000 more at 10%. if the yearly interest from the three investments is $3090 how much is invested altogether? \n" ); document.write( "
Algebra.Com's Answer #105309 by checkley77(12844)\"\" \"About 
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.08x+.09*2x+.10(x+1000)=3090
\n" ); document.write( ".08x+.18x+.10x+100=3090
\n" ); document.write( ".36x=3090-100
\n" ); document.write( ".36x=2990
\n" ); document.write( "x=2990/.36
\n" ); document.write( "x=$8305.56 amount invsted @ 8%
\n" ); document.write( "2*8305.56=16,611.11 invested @ 9%
\n" ); document.write( "9305.56+1000=90305.56 invested @ 10%
\n" ); document.write( "proof:
\n" ); document.write( ".08*8302.56+.09*16611.11+.10*9305.56=3090
\n" ); document.write( "664.20+1495+930.56=3090
\n" ); document.write( "3090~3090
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