document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=144560>Question 144560</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with the following problem...I have NO idea what to do!! Thanks in advance for your help!!!\r<BR>\n" );
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document.write( "Anne and Nancy use a metal alloy that is 15.9% copper to make jewelry. How many ounces of an alloy that is 15% copper must be mixed with an alloy that is 18% copper to form 90 ounces of the desired alloy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #105302 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=105302\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .15x+.18(90-x)=.159*90<BR>\n" );
document.write( ".15x+16.2-.18x=14.31<BR>\n" );
document.write( "-.03x=14.31-16.2<BR>\n" );
document.write( "-.03x=-1.89<BR>\n" );
document.write( "x=-1.89/-.03<BR>\n" );
document.write( "x=63 oz. of 155 copper is needed.<BR>\n" );
document.write( "90-63=27 oz. of 18% copper is needed.<BR>\n" );
document.write( "proof:<BR>\n" );
document.write( ".15*63+.18*27=14.31<BR>\n" );
document.write( "9.45+4.86=14.31<BR>\n" );
document.write( "14.31=14.31\r<BR>\n" );
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document.write( " </SPAN>\n" );
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