document.write( "Question 144507: A cattle train left Miami and traveles toward New York, 14 hours later a diesel train left traveling at 45km/h in an effort to catch up to the cattle train. After traveling four hours the diesel train finally caught up.\r
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Algebra.Com's Answer #105254 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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A cattle train left Miami and travels toward New York, 14 hours later a diesel train left traveling at 45km/h in an effort to catch up to the cattle train. After traveling four hours the diesel train finally caught up.
\n" ); document.write( "What was the cattle train's average speed?
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\n" ); document.write( "Let x = speed of the cattle train
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\n" ); document.write( "Write a distance equation; dist = speed * time
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\n" ); document.write( "we know when the two trains will have traveled the same distance.
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\n" ); document.write( "We know from the given information that the cattle train will have been traveling for 14 + 4 = 18 hrs
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\n" ); document.write( "Cattle dist = diesel dist
\n" ); document.write( "18x = 4*45
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\n" ); document.write( "18x = 180
\n" ); document.write( "x = $\"180%2F18\"$
\n" ); document.write( "x = 10 mph is the speed of the cattle train
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\n" ); document.write( "Check the solution by finding the distance of each:
\n" ); document.write( "18 * 10 = 180 mi
\n" ); document.write( "4 * 45 = 180 mi \n" ); document.write( "

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