document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=21810>Question 21810</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a chemist needs 10 liters of a 50% salt solution.  all that is available is a 20% salt solution and a 70% salt solution.  how much of each of the 2 solutions should she mix to obtain her desired solution?<BR>\n" );
document.write( "a) 5 liters of the 20% solution; 5 liters of the 70% solution<BR>\n" );
document.write( "b) 3 liters of the 20% solution; 7 liters of the 70% solution<BR>\n" );
document.write( "c) 2 liters of the 20% solution; 8 liters of the 70% solution<BR>\n" );
document.write( "d) 4 liters of the 20% solution; 6 liters of the 70% solution </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10525 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10525\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 20x+70(10-x)=50(10)<BR>\n" );
document.write( "20x+700-70x=500<BR>\n" );
document.write( "-50x=-200<BR>\n" );
document.write( "x=4<BR>\n" );
document.write( "10-4=6<BR>\n" );
document.write( "Hence, for 20% there should be 4L of solution added and for 70% there should be 6L if solution added </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );