document.write( "Question 144491: Hi. I'm stuck on a word problem. Could someone please help me? Thank you in advance!!\r
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document.write( "In 1993 the life expectancy of males was 63.7 years. In 1999, it was 66.8. Let E represent the life expectancy in years and let t represent number of years since 1993. \r
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document.write( "I need to write a linear equation that fits the data. E(t)= ___t + ___\r
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document.write( "Also I need to use the function to predict the life expectancy of males in 2007.
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document.write( "E(14)=____ \n" );
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Algebra.Com's Answer #105247 by vleith(2983)![]() ![]() ![]() You can put this solution on YOUR website! You are given two points, so first find the slope between them.\r \n" ); document.write( "\n" ); document.write( "slope = (y2 - y1)/(x2 - x1) \n" ); document.write( "slope = (66.8 - 63.7)/(1999 - 1993) \n" ); document.write( "slope = 3.1/6 = 0.516\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, using this equation, we see that in 1193, t = 0 (year - 1993) \n" ); document.write( "This yields 63.7\r \n" ); document.write( "\n" ); document.write( "In the year 1999, t = (1999-1993) = 6 \n" ); document.write( "E(6) = 0.516(6) + 63.7 = 66.8\r \n" ); document.write( "\n" ); document.write( "Now let's assume the same model is OK through 2007. t = (2007 - 1993) = 14 \n" ); document.write( "E(14) = 0.516*14 + 63.7 \n" ); document.write( "E(14) = 70.924\r \n" ); document.write( "\n" ); document.write( "Make sense?\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |