document.write( "Question 144503: Factor the polynomial completely:\r
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Algebra.Com's Answer #105244 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"%282x%2B3%29%5E3+-+64\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "Let a=2x+3\r
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\n" ); document.write( "\n" ); document.write( "So we now have \"a%5E3+-+64+\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28a%29%5E3-%284%29%5E3\" Rewrite \"a%5E3\" as \"%28a%29%5E3\". Rewrite \"64\" as \"%284%29%5E3\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28a-4%29%28%28a%29%5E2%2B%28a%29%284%29%2B%284%29%5E2%29\" Now factor by using the difference of cubes formula. Remember the difference of cubes formula is \"A%5E3-B%5E3=%28A-B%29%28A%5E2%2BAB%2BB%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28a-4%29%28a%5E2%2B4a%2B16%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"%282x%2B3-4%29%28%282x%2B3%29%5E2%2B4%282x%2B3%29%2B16%29\" Now replace each \"a\" with \"2x%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "\"%282x%2B3-4%29%284x%5E2%2B12x%2B9%2B4%282x%2B3%29%2B16%29\" Foil\r
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\n" ); document.write( "\n" ); document.write( "\"%282x%2B3-4%29%284x%5E2%2B12x%2B9%2B8x%2B12%2B16%29\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"%282x-1%29%284x%5E2%2B20x%2B37%29\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So \"%282x%2B3%29%5E3+-+64\" factors to \"%282x-1%29%284x%5E2%2B20x%2B37%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"%282x%2B3%29%5E3+-+64=%282x-1%29%284x%5E2%2B20x%2B37%29\"
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