document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=144478>Question 144478</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321437268/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> How many gallons of a 12% solution must be mixed with a 20% soltion to get 10 gallons of a 14% solution?                                                                                                                                    </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #105237 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=105237\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many gallons of a 12% solution must be mixed with a 20% solution to get 10 gallons of a 14% solution?                                                                                                                                   <BR>\n" );
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document.write( "Let x = amt of 12% solution required<BR>\n" );
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document.write( "The resulting total amt is to be 10 gal therefore:<BR>\n" );
document.write( "(10-x) = amt of 20% solution<BR>\n" );
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document.write( "we will use the decimal equiv of percent:<BR>\n" );
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document.write( ".12x + .20(10-x) = .14(10)<BR>\n" );
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document.write( ".12x + 2 - .20x = 1.4<BR>\n" );
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document.write( ".12x - .20x = 1.4 - 2<BR>\n" );
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document.write( "-.08x = -.6<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-.6%29%2F%28-.08%29 ALIGN=MIDDLE  ALT=\"%28-.6%29%2F%28-.08%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = +7.5 gal of 12% solution required<BR>\n" );
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document.write( "Check solution in the original equation (2.5 gal of the 20% solution needed)<BR>\n" );
document.write( ".12(7.5) + .2(2.5) = .14(10)<BR>\n" );
document.write( ".9 + .5 = 1.4, confirms our solution<BR>\n" );
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document.write( "Was this easy to understand now? </SPAN>\n" );
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