document.write( "Question 144445: Steve traveled 200 miles at a certain speed. Had he gone 10 mph faster, the trip would have taken 1 hour less. Find the speed of his vehicle.
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document.write( "How would you turn this into an algebraic equation and solve it. I'm sorry if i seem to be a total idiot. But i have no CLUE. Please help me someone!! \n" );
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Algebra.Com's Answer #105186 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Tricky problem. \n" ); document.write( "Call the speed S and the time H (for hours). \n" ); document.write( "The distance is 200, and is Speed x Hours, S times H.\r \n" ); document.write( "\n" ); document.write( "Going faster takes less time. 200 = (S + 10) times (H-1)\r \n" ); document.write( "\n" ); document.write( "We have 2 equations in 2 unknowns now.\r \n" ); document.write( "\n" ); document.write( "SH = 200 eqn 1 \n" ); document.write( "(S+10)(H-1) = 200 eqn 2\r \n" ); document.write( "\n" ); document.write( "SH + 10H -S -10 = 200, or \n" ); document.write( "SH + 10H -S -10 = SH \n" ); document.write( "10H -S -10 = 0 \n" ); document.write( "S = 200/H\r \n" ); document.write( "\n" ); document.write( "10H - 200/H - 10 = 0 \n" ); document.write( "Multiply by H \n" ); document.write( " \n" ); document.write( "Divide by 10 \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "H = 5, or -4. -4 hours makes no sense, so it's discarded. \n" ); document.write( "The time is 5 hours to go 200 miles. So the speed is 40 mph \n" ); document.write( "Going 50 mph would take 4 hours, so the answer is correct. \n" ); document.write( " |