document.write( "Question 144445: Steve traveled 200 miles at a certain speed. Had he gone 10 mph faster, the trip would have taken 1 hour less. Find the speed of his vehicle.
\n" ); document.write( "How would you turn this into an algebraic equation and solve it. I'm sorry if i seem to be a total idiot. But i have no CLUE. Please help me someone!! \n" ); document.write( "
Algebra.Com's Answer #105182 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Steve traveled 200 miles at a certain speed. Had he gone 10 mph faster, the trip would have taken 1 hour less. Find the speed of his vehicle.
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\n" ); document.write( "Before speed change DATA:
\n" ); document.write( "distance = 200 miles ; speed = x mph ; time = d/r = 200/x hrs.
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\n" ); document.write( "After speed change DATA:
\n" ); document.write( "distance = 200 miles ; speed = \"x+10\" mph ; time = d/r = 200/(x+10)
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\n" ); document.write( "EQUATIOn:
\n" ); document.write( "original time - new time = 1 hr
\n" ); document.write( "200/x - 200/(x+10) = 1
\n" ); document.write( "200x+ 2000 - 200x = x(x+10)
\n" ); document.write( "x^2+10x-2000 = 0
\n" ); document.write( "(x+50)(x-40) = 0
\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 40 mph (original speed)
\n" ); document.write( "x + 10 = 50 mph (newspeed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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