document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=144442>Question 144442</A>: <I><SPAN STYLE=\"word-break: break-all;\"> On this problem, just like the other, i don't understand how you can have the solution equal to zero. It says that i need to use the discriminant to determine the number of solutions of the quadratic equation, and whether the solutions are real or complex.  How do i determine the number and types of solutions. For this equations 2x2 - 10x + 25 = 0. Please help me someone. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #105177 by </B><A HREF=/tutors/aboutme.mpl?userid=nabla><B>nabla(475)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nabla><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=105177\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The discriminant is b^2-4ac for equation ax^2+bx+c=0. For your problem that is 100-200=-100. Now, if we used this in the quadratic formula, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > , we would get a negative square root, which by definition causes the equation to have no real roots. (The solutions will consist of two complex numbers because of the +/- and the discriminant not equaling 0.)  </SPAN>\n" );
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