document.write( "Question 144400: The length of rectangle is fixed at 11cm. what widths will make the permeter greater than 92cm?\r
\n" ); document.write( "\n" ); document.write( "11x-9<-53 =?\r
\n" ); document.write( "\n" ); document.write( "6(3+4x)-8>154=\r
\n" ); document.write( "\n" ); document.write( "Please help!
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Algebra.Com's Answer #105147 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
Perimeter = 2*length + 2* width
\n" ); document.write( "\"92%3C+2%2Al+%2B+2%2Aw\"
\n" ); document.write( "\"92+%3C+2%2A11+%2B+2%2Aw\"
\n" ); document.write( "\"92+%3C+22+%2B+2w+\"
\n" ); document.write( "\"70+%3C+2w\"
\n" ); document.write( "\"35+%3C+w+\" so any width larger than 35cm will do\r
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\n" ); document.write( "\n" ); document.write( "11x-9<-53
\n" ); document.write( "11x < -44
\n" ); document.write( "x < -4\r
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\n" ); document.write( "\n" ); document.write( "6(3+4x)-8>154
\n" ); document.write( "18 + 24x -8 > 154
\n" ); document.write( "10 + 24x > 154
\n" ); document.write( "24x > 144
\n" ); document.write( "x > 6\r
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