document.write( "Question 21784: log(2+x)-log(x)=log 11 could you help explain how to do this \n" ); document.write( "
Algebra.Com's Answer #10514 by Earlsdon(6294)\"\" \"About 
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Solve for x:
\n" ); document.write( "\"log%28%282%2Bx%29%29+-+log%28x%29+=+log%2811%29\" Apply the Quotient rule for logarithms to the left side. \"log%28M%29+-+log%28N%29+=+log%28%28M%2FN%29%29\"
\n" ); document.write( "\"log%28%28%282%2Bx%29%2Fx%29%29+=+log%2811%29\" If log a = log b, then a = b
\n" ); document.write( "\"%282%2Bx%29%2Fx+=+11\" Multiply both sides by x.
\n" ); document.write( "\"2%2Bx+=+11x\" Subtract x from both sides.
\n" ); document.write( "\"2+=+10x\" Divide both sides by 10.
\n" ); document.write( "\"x+=+2%2F10\"
\n" ); document.write( "\"x+=+0.2\"\r
\n" ); document.write( "\n" ); document.write( "Check: Use your calculator or a table of logarithms to find the values of the logs.\r
\n" ); document.write( "\n" ); document.write( "\"log%28%282%2B0.2%29%29+-+log%280.2%29+=+1.04139\"
\n" ); document.write( "\"log%2811%29+=+1.04139\"
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