document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=144377>Question 144377</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am tring to do the final worksheet of the term and I just don't understand it well enough to take the final. If anyone can help me with these equations I would really appreciate it. I have to find the vertex and intercepts and graph the equation.<BR>\n" );
document.write( "f(x)= -2x^2-5x+3<BR>\n" );
document.write( "Thanks again. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #105126 by </B><A HREF=/tutors/aboutme.mpl?userid=nabla><B>nabla(475)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nabla><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=105126\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First we will factor:\r<BR>\n" );
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document.write( "f(x)=-(x+3)(2x-1).\r<BR>\n" );
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document.write( "Find the intercepts first:<BR>\n" );
document.write( "y-intercept:<BR>\n" );
document.write( "f(0)=-(3)(-1)=3. That gives (0,3).\r<BR>\n" );
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document.write( "x-intercepts:<BR>\n" );
document.write( "0=-(x+3)(2x-1) implies x=-3 or x=1/2. That gives (-3,0) and (1/2,0)\r<BR>\n" );
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document.write( "Now, the x-coordinate here will be -b/2a  where f(x)=ax^2+bx+c. Thus, x=5/(-4)=-4/5 will be the x-coordinate of the vertex. Plug this in to get the y value: f(-4/5)=-2(16/25)-5(-4/5)+3=-32/25+175/25=143/25; So, (-4/5,143/25).\r<BR>\n" );
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document.write( "Note that this will be concave down because the coefficient of the x^2 term is negative.<BR>\n" );
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