document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=2465>Question 2465</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help me with this word problem that I am struggling with?<BR>\n" );
document.write( "The distance D between a fixed spring and the floor is a linear function of the weight w attached to the bottom of the spring. The spring is 12 inches from the floor when the weight is 2 grams, and the spring is 7 inches from the floor when the weight is 4 grams. Write D as a linear function of w.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1051 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1051\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Let D = aW +b,<BR>\n" );
document.write( " when W = 2, D = 12, so 12 = 2a + b...(1)<BR>\n" );
document.write( " when W = 4, D = 7, so 7 = 4a + b...(2)\r<BR>\n" );
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document.write( " (2)-(1): 2a = -5, or a = -2.5,<BR>\n" );
document.write( "  hence b = 12+ 2*2.5 = 17.\r<BR>\n" );
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document.write( " Answer: D = -2.5W + 17.\r<BR>\n" );
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document.write( " Kenny </SPAN>\n" );
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