document.write( "Question 21794: I am a parent with 9th grde algebra problems with my son. We are both lost and I need help. The worksheet says Equations and rational numbers.I cannot identify where to begin here is an example problem, 3a+1 =2 the 3a+1 has a line under it like a fraction over 5. Some of the others are like this, 1/4h+1/2=1 or 3/5x+1/2=4 1/10 \n" ); document.write( "
Algebra.Com's Answer #10508 by queenofit(120)![]() ![]() ![]() You can put this solution on YOUR website! I will work your example for you, if you have futher questions you may ask. \n" ); document.write( "Remember when working with fractions you must find the LCD (least common denominator)remember you are trying to get all the variables and numbers on different sides of the = sign. I find it easier to explain it to begining students as if the numbers are one \"team\" and the variables are the other \"team\". The teams oppose each other with the = sign being the middle man. each team must equal the other to be fair....understand? \n" ); document.write( "ok your example was \n" ); document.write( "3a + 1 = 2 \n" ); document.write( "______ \n" ); document.write( " 5 The first thing is to get rid of the 5 by multiplying both sides \n" ); document.write( " by 5. you do this because one side is a fraction which is actually \n" ); document.write( " indicating division by 5. \n" ); document.write( "5 * 3a + 1 \n" ); document.write( " ______ \n" ); document.write( " 5 = 2*5 this will get rid of your fraction, the 5s on the left \n" ); document.write( " cancel each other out and you are left with\r \n" ); document.write( "\n" ); document.write( "3a + 1 = 10 Move your \"team\" players to their correct side \n" ); document.write( "3a=10-1 when you move the \"team\" players across the = sign they \n" ); document.write( " change from neg to pos or pos to neg. understand? \n" ); document.write( "3a=9 here you still have a team member on the other side. \n" ); document.write( " since 3 is actually multiplying with the \"a\", you would \n" ); document.write( " divide each side by 3 to cancel out the 3 in front of the \n" ); document.write( " \"a\" \n" ); document.write( "3a = 9 \n" ); document.write( "-- -- \n" ); document.write( "3 3\r \n" ); document.write( "\n" ); document.write( "a=3\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |