document.write( "Question 21795: Solve.\r
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\n" ); document.write( "\n" ); document.write( " |2x+9| <3
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Algebra.Com's Answer #10507 by AnlytcPhil(1807)\"\" \"About 
You can put this solution on YOUR website!
Solve. \r\n" );
document.write( "2(x-3)=5x+9 \r\n" );
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document.write( "Use distributive property to remove parentheses:\r\n" );
document.write( " 2x - 6 = 5x + 9\r\n" );
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document.write( "Add +6 to both sides\r\n" );
document.write( " 2x - 6 = 5x + 9\r\n" );
document.write( "    + 6      + 6\r\n" );
document.write( "-----------------\r\n" );
document.write( " 2x     = 5x + 15\r\n" );
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document.write( "Add -5x to both sides:\r\n" );
document.write( " 2x     = 5x + 15\r\n" );
document.write( "-5x      -5x\r\n" );
document.write( "-----------------\r\n" );
document.write( "-3x     =      15\r\n" );
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document.write( "Divide both sides by -3\r\n" );
document.write( "-3x/-3  =      15/-3\r\n" );
document.write( "     x  = -5\r\n" );
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document.write( "-------------------------\r\n" );
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document.write( "|2x+9| < 3\r\n" );
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document.write( "Learn the two rules:\r\n" );
document.write( "If B is a positive number, then\r\n" );
document.write( "1. |A| < B can be written  \" -B < A < +B \".\r\n" );
document.write( "2. |A| > B can be writter \" A < -B OR A > +B \".\r\n" );
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document.write( "           |2x+9| < 3 can be written\r\n" );
document.write( "       -3 < 2x+9 < 3\r\n" );
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document.write( "Add -9 to all three \"sides\"\r\n" );
document.write( "       -3 < 2x+9 < 3\r\n" );
document.write( "       -9     -9  -9\r\n" );
document.write( "      ---------------\r\n" );
document.write( "      -12 < 2x   < -6\r\n" );
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document.write( "Divide all three sides by 2\r\n" );
document.write( "       -6 <  x   < -3\r\n" );
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document.write( "
Edwin
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