document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=144318>Question 144318</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve the solution\r<BR>\n" );
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document.write( "y=3^(2x+1)<BR>\n" );
document.write( "y=9^(4-2x)\r<BR>\n" );
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document.write( "do you make the powers = one another for 2x+1=4-2x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #105067 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=105067\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To equate the powers you have to have equal bases:<BR>\n" );
document.write( "y=3^(2x+1)<BR>\n" );
document.write( "y=9^(4-2x) <BR>\n" );
document.write( "------------<BR>\n" );
document.write( "y = 3^(2x+1)<BR>\n" );
document.write( "y = 3^[2(4-2x)]<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "2x+1 = 2(4-2x)<BR>\n" );
document.write( "2x+1 = 8-4x<BR>\n" );
document.write( "6x = 7<BR>\n" );
document.write( "x = 7/6<BR>\n" );
document.write( "===========<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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