document.write( "Question 144312: Solve the solution 7x-8y=24 and xy^2=1
\n" ); document.write( "I've done the following so far x=1/y^2\r
\n" ); document.write( "\n" ); document.write( "substitute so...7(1/y^2)-8y=24
\n" ); document.write( " 7=24y^2+8y^3\r
\n" ); document.write( "\n" ); document.write( "let t=y^2...7=24t+8t^2......did I do this correctly?
\n" ); document.write( " 8(t^2 +3t)=7
\n" ); document.write( " 8(t^2+3t+9/4)=7+18 complete the square
\n" ); document.write( " 8(t+3/2)^2=25...if I have done this correctly, then what are my next steps...
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Algebra.Com's Answer #105064 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
7=24y^2+8y^3\r
\n" ); document.write( "\n" ); document.write( "let t=y^2...7=24t+8t^2......did I do this correctly?\r
\n" ); document.write( "\n" ); document.write( "No. Close but no cigar\r
\n" ); document.write( "\n" ); document.write( "let t=y^2...7=24t+8t^2. if you put y^2 back in to t, you get 7=24y^2+8y^4.\r
\n" ); document.write( "\n" ); document.write( "0 = 8y^3 + 24y^2 -7
\n" ); document.write( "Try this ? --> http://www.1728.com/cubic2.htm
\n" ); document.write( "http://www.1728.com/cubic.htm\r
\n" ); document.write( "\n" ); document.write( "Not pretty.
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