document.write( "Question 21795: Solve.\r
\n" ); document.write( "\n" ); document.write( "2(x-3)=5x+9\r
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\n" ); document.write( "\n" ); document.write( " |2x+9| <3
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Algebra.Com's Answer #10506 by queenofit(120)\"\" \"About 
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2(x-3)=5x+9
\n" ); document.write( "2x-6=5x+9
\n" ); document.write( "2x-5x=6+9
\n" ); document.write( "-3x=15
\n" ); document.write( "x=-5\r
\n" ); document.write( "\n" ); document.write( "On the absolute value question remember there are two answers. The absolute value can be either neg or pos. so set up two equations\r
\n" ); document.write( "\n" ); document.write( "2x+ 9 < 3 and -2x- 9 < 3
\n" ); document.write( "2x< -9 +3 -2x < 9 + 3
\n" ); document.write( "2X<-6 -2X < 12
\n" ); document.write( "X<-3 X>-6 remember to flip your sign
\n" ); document.write( " when you divide by a neg.
\n" ); document.write( "so you will have -3>x<-6
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