document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=144207>Question 144207</A>: <I><SPAN STYLE=\"word-break: break-all;\"> an aluminum plate is made according to the following dimensions. The outer radius is 10 inches and the inner radius is 3 inches. Use p=3.14 as an approximate value. (a) how many square inches in area is the aluminum plate (the shaded region)? (b) If the cost to construct the plate is &7.50 per square inch, what is the construction cost? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #105055 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=105055\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> area=pir^2<BR>\n" );
document.write( "area=3.14*5^2<BR>\n" );
document.write( "area=3.14*25<BR>\n" );
document.write( "area=78.5 in^2 for the total area of the 10 inch plate.<BR>\n" );
document.write( "area=3.14*3^2<BR>\n" );
document.write( "area=3.14*9<BR>\n" );
document.write( "area=28.26 in^2 for the inner circle.<BR>\n" );
document.write( "78.5-28.26=50.24 is the area of the 10 in. plate with a 3 in. hole. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );