document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=144228>Question 144228</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I write the equation for the question below, and then how do I solve it.\r<BR>\n" );
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document.write( "Questions: One angle is 3 times another. If the two angles are complimentary, what are the angle measures?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #104993 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=104993\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One angle is 3 times another. If the two angles are complimentary, what are the angle measures? <BR>\n" );
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document.write( "x = 3y<BR>\n" );
document.write( "x+y = 90<BR>\n" );
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document.write( "solve by substitution:<BR>\n" );
document.write( "3y+y = 90<BR>\n" );
document.write( "4y = 90 <BR>\n" );
document.write( "y = 22.5 degrees<BR>\n" );
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document.write( "Substitute into x = 3y to get <BR>\n" );
document.write( "x = 3*22.5 = 67.5 degrees\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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