document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=144223>Question 144223</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help me solve this system by substitution?\r<BR>\n" );
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document.write( "y=3x<BR>\n" );
document.write( "x+y=8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #104986 by </B><A HREF=/tutors/aboutme.mpl?userid=nabla><B>nabla(475)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nabla><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=104986\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's solve this with words at first:<BR>\n" );
document.write( "y is the same as 3x.<BR>\n" );
document.write( "Thus, x plus y must be x+3x. This is 4x. Thus, 4x must be 8. The value for x that makes this true is 2. Moreover, y must now be 3*2=6.\r<BR>\n" );
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document.write( "In symbols:\r<BR>\n" );
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document.write( "y=3x<BR>\n" );
document.write( "x+y=8\r<BR>\n" );
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document.write( "-->\r<BR>\n" );
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document.write( "x+3x=8<BR>\n" );
document.write( "4x=8<BR>\n" );
document.write( "x=2\r<BR>\n" );
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document.write( "y=3(2)=6. </SPAN>\n" );
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