document.write( "Question 144219: can someone tell me the answer to
\n" ); document.write( "factor: 3x2-19x-40 (i think you'd say 3xsquared(the 2 is up higher)
\n" ); document.write( "and
\n" ); document.write( "factor: 9x2-12x+4 (i think you'd say 3xsquared(the 2 is up higher)
\n" ); document.write( "i've been trying for hours, i just don't get it and it's 3am and i need to be up in 3 hours \n" ); document.write( "
Algebra.Com's Answer #104985 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
3x^2 - 19x - 40
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\n" ); document.write( "First write it:
\n" ); document.write( "(3x ___)(x ___)
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\n" ); document.write( "You know the values in the blanks will be factors of -40,
\n" ); document.write( "(one will be neg, the other positive):
\n" ); document.write( "1, 40
\n" ); document.write( "2, 20
\n" ); document.write( "4, 10
\n" ); document.write( "5, 8
\n" ); document.write( "Because the middle term is neg, the larger factor has to be negative
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\n" ); document.write( "FOIL these values until you get the given expression:
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\n" ); document.write( "(3x + 5)(x - 8) FOILs to 3x^2 - 24x + 5x - 40 which is:
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\n" ); document.write( "3x^2 - 19x - 40
\n" ); document.write( "FOIL these values until the
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\n" ); document.write( "factor: 9x^2 - 12x + 4
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\n" ); document.write( "The clue on this one is that both the coefficient of x (9) and 4 are perfect squares.
\n" ); document.write( "Try these values first.
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\n" ); document.write( "Since the middle term is neg and the 3rd terms is positive it must be:
\n" ); document.write( "(3x - 2)(3x - 2) or (3x-2)^2
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\n" ); document.write( "FOIL this and you get the original expression:
\n" ); document.write( "9x^2 - 6x - 6x + 4 = 9x^2 - 12x + 4
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\n" ); document.write( "Practice doing these and it will become pretty easy. \n" ); document.write( "
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