document.write( "Question 144194: A sprinter who average 30ft/sec. completed a race 1 sec before another sprinter who average 28ft/sec.What was the distance of the race. \n" ); document.write( "
Algebra.Com's Answer #104963 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! if the winner won by 1sec, he also won by 28ft; because the second sprinter ran 28ft/sec\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the difference in their speeds was 2ft/sec; so to get a 28ft lead, the winner must have run for 14sec (28/2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "30ft/sec for 14sec is 420ft (140yd)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "using equations __ let x=distance __ d=rt __ t=d/r\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x/28=(x/30)+1 __ multiplying by 420 (LCM) __ 15x=14x+420 __ x=420 \n" ); document.write( " |