document.write( "Question 144184: Please help!! The problem is 4m^2 +25=20m.
\n" ); document.write( "This is what I have.. 4m^2- 20m+ 25=0. I used the formula b^2 - 4ac and the answer is 400-400=0. The discriminant is zero so there is only one answer. But I can't figure out the #.. Any help is greatly appreciated!!! Thanks.
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Algebra.Com's Answer #104947 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"4m%5E2%2B25=20m\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"4m%5E2%2B25-20m=0\" Subtract 20m from both sides. \r
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\n" ); document.write( "\n" ); document.write( "\"4m%5E2-20m%2B25=0\" Rearrange the terms \r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for m:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"am%5E2%2Bbm%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"m+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"4%2Am%5E2-20%2Am%2B25=0\" ( notice \"a=4\", \"b=-20\", and \"c=25\")\r
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\n" ); document.write( "\n" ); document.write( "\"m+=+%28--20+%2B-+sqrt%28+%28-20%29%5E2-4%2A4%2A25+%29%29%2F%282%2A4%29\" Plug in a=4, b=-20, and c=25\r
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\n" ); document.write( "\n" ); document.write( "\"m+=+%2820+%2B-+sqrt%28+%28-20%29%5E2-4%2A4%2A25+%29%29%2F%282%2A4%29\" Negate -20 to get 20\r
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\n" ); document.write( "\n" ); document.write( "\"m+=+%2820+%2B-+sqrt%28+400-4%2A4%2A25+%29%29%2F%282%2A4%29\" Square -20 to get 400 (note: remember when you square -20, you must square the negative as well. This is because \"%28-20%29%5E2=-20%2A-20=400\".)\r
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\n" ); document.write( "\n" ); document.write( "\"m+=+%2820+%2B-+sqrt%28+400%2B-400+%29%29%2F%282%2A4%29\" Multiply \"-4%2A25%2A4\" to get \"-400\"\r
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\n" ); document.write( "\n" ); document.write( "\"m+=+%2820+%2B-+sqrt%28+0+%29%29%2F%282%2A4%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"m+=+%2820+%2B-+0%29%2F%282%2A4%29\" Simplify the square root \r
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\n" ); document.write( "\n" ); document.write( "\"m+=+%2820+%2B-+0%29%2F8\" Multiply 2 and 4 to get 8\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
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\n" ); document.write( "\n" ); document.write( "\"m+=+%2820+%2B+0%29%2F8\" or \"m+=+%2820+-+0%29%2F8\"\r
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\n" ); document.write( "\n" ); document.write( "Lets look at the first part:\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2820+%2B+0%29%2F8\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=20%2F8\" Add the terms in the numerator\r
\n" ); document.write( "\n" ); document.write( "\"m=5%2F2\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So one answer is\r
\n" ); document.write( "\n" ); document.write( "\"m=5%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Now lets look at the second part:\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2820+-+0%29%2F8\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=20%2F8\" Subtract the terms in the numerator\r
\n" ); document.write( "\n" ); document.write( "\"m=5%2F2\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So another answer is\r
\n" ); document.write( "\n" ); document.write( "\"m=5%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the only solution is\r
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\n" ); document.write( "\n" ); document.write( "\"m=5%2F2\"
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