document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=21755>Question 21755</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three forces, each of which is perpendicular to the other two, act on an object. If the magnitude of these forces are 6N, 10N, and 15N respectively, find the magnitude and direction of the resultant, and thier angles.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10487 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10487\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Label the rectangluar prism.<BR>\n" );
document.write( "|AD| = 6N<BR>\n" );
document.write( "|AB|=15N<BR>\n" );
document.write( "|AE|=10N<BR>\n" );
document.write( "|AG|=Endpoint<BR>\n" );
document.write( "|AG|^2=5^2+10^2+15^2<BR>\n" );
document.write( "simplify |AG|=19N   <GBA = cosine (alpha) =15/19 /// <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=alpha ALIGN=MIDDLE  ALT=\"alpha\"   DISABLED_style= \"max-width:90%; height:auto;\" >=38degrees /// <EAG = cosine (beta) =10/19 /// beta=58degrees<BR>\n" );
document.write( "Hence, the resultant force is 19N making an angle of 38 and 58 degrees\r<BR>\n" );
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document.write( "Click on show work to see the work because it did not come up right<BR>\n" );
document.write( " </SPAN>\n" );
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