document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=144075>Question 144075</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have having problems with solving the following.  If anyone can provide me with the steps it would be appreciated.\r<BR>\n" );
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document.write( "The measurement of land area assumes that the land is horizontal.  What is the actual area of a 4.38 ha field if it is on a 15% slope.  \r<BR>\n" );
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document.write( "Thanks, much appreciated. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #104869 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=104869\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assuming the field is a square and has area = 4.58 on the horizontal,<BR>\n" );
document.write( "it has a side of sqrt(4.58) = 2.1401..<BR>\n" );
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document.write( "The 15% slope has a gradiant of 0.15*90 degrees = 13.5 degrees<BR>\n" );
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document.write( "The horizontal side projects to a hypotenuse of a right triangle<BR>\n" );
document.write( "with an angle of 13.5 degrees adjacent to the 2.1401.. base.<BR>\n" );
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document.write( "The length of that projected hypotenuse is 2.1401../cos(13.5)<BR>\n" );
document.write( "= 2.2009..<BR>\n" );
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document.write( "Therefore the horizontal square projects to a quadrilateral with area <BR>\n" );
document.write( "= 2.2009*2.1401 = 4.71012 ha<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  </SPAN>\n" );
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