document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=144076>Question 144076</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If anyone could help with the following.  I am having a little trouble getting the correct answer for this question.\r<BR>\n" );
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document.write( "The rade of a hill is 8.6%.  If the road up the hill is 3.55 km long, what is the angle from the horizontal and the change in vertical and horizontal distances.\r<BR>\n" );
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document.write( "Any help would be appreciated as I just cant seem to get the correct answer. Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #104867 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=104867\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The grade of a hill is 8.6%. If the road up the hill is 3.55 km long, what is the angle from the horizontal and the change in vertical and horizontal distances. <BR>\n" );
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document.write( "Draw the picture.<BR>\n" );
document.write( "If you have a right triangle extending up the hill to the right,<BR>\n" );
document.write( "the small angle on the left is 8.6% = 0.086*90 = 7.74 degrees<BR>\n" );
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document.write( "The hypotenuse is 3.55 km<BR>\n" );
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document.write( "The vertical side opposite the 7.74 degree angle = 3.55(sin(7.74))=0.4781..km<BR>\n" );
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document.write( "The base side = 3.55(cos(7.74)) = 3.51766..km<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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