document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=144089>Question 144089</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In the problem, a square with a circumference of 5 is inside of a square. The answer to the problem is 1/4 the area not covered by the circle. What is the answer and how did you get it. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #104862 by </B><A HREF=/tutors/aboutme.mpl?userid=nabla><B>nabla(475)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nabla><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=104862\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> C=pi*diameter<BR>\n" );
document.write( "thus pi*d=5<BR>\n" );
document.write( "and d=5/pi\r<BR>\n" );
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document.write( "d^2 will be the area of the square.<BR>\n" );
document.write( "d^2=25/(pi)^2\r<BR>\n" );
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document.write( "Now, pi*r^2=Area of circle\r<BR>\n" );
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document.write( "and r=1/2d=(1/2)(5/pi)=(5/(2pi))\r<BR>\n" );
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document.write( "Thus, A= pi*(25/(4pi^2))=25/(4pi)\r<BR>\n" );
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document.write( "The left over area will be 5/(pi)^2-25/(4pi). </SPAN>\n" );
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