document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=144066>Question 144066</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A radiator specialist needs 10 gallons<BR>\n" );
document.write( "of a solution of 50% antifreeze.<BR>\n" );
document.write( "he has a container of 90% antifreeze<BR>\n" );
document.write( "and he has a container 40% antifreeze<BR>\n" );
document.write( "How many gallons of each solution should<BR>\n" );
document.write( "he use to mix together to get 10 gallons of <BR>\n" );
document.write( "50% antifreeze? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #104848 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=104848\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x=\"gallons of 90%\", so 10-x=\"gallons of 40%\"\r<BR>\n" );
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document.write( "(90%)(x)+(40%)(10-x)=(50%)(10) __ multiplying by 10 and distributing __ 9x+40-4x=50\r<BR>\n" );
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document.write( "subtracting 40 __ 5x=10 __ x=2 </SPAN>\n" );
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