document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=144072>Question 144072</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0618306056/algebrahomeworkh>Beginning Algebra with Applications</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Solve by factoring.<BR>\n" );
document.write( "The radius of a circle is increased by 3 in., which increases the area by 100 in^2. Find the radius of the original circle. Round to the nearest hundredth.<BR>\n" );
document.write( "Please answer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #104847 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=104847\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> pi*r^2=A original<BR>\n" );
document.write( "pi*(r+3)^2=A+100 new<BR>\n" );
document.write( "pi(r^2+6r+9)=A+100<BR>\n" );
document.write( "pi(r^2+6r+9)-100=A<BR>\n" );
document.write( "pi(r^2+6r+9)-100=pi*r^2<BR>\n" );
document.write( "r^2+6r+9-(100/pi)=r^2<BR>\n" );
document.write( "6r+9-31.83=0<BR>\n" );
document.write( "6r=22.83<BR>\n" );
document.write( "r=3.81\"<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "pi*3.81^2=45.49<BR>\n" );
document.write( "pi*6.81^2=145.49<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );