document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=144056>Question 144056</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hello<BR>\n" );
document.write( "im in high school righ now, learning about conics<BR>\n" );
document.write( "and i have a question on how to find an equaion of a circle if:<BR>\n" );
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document.write( "circle with center at (-5,1) and radius 6 \r<BR>\n" );
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document.write( "also what it he line(s) of symmetry?<BR>\n" );
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document.write( "thank you so much <BR>\n" );
document.write( "and i will appreciate very much if you could<BR>\n" );
document.write( "respond soon as possible<BR>\n" );
document.write( "i have a quiz tomorrow <BR>\n" );
document.write( "thank you !!!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #104844 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=104844\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The equation of any circle is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2 ALIGN=MIDDLE  ALT=\"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > where (h,k) is the center and r is the radius. So in your case, the center is (-5,1) which means that h=-5 and k=1. Also the radius is 6, so r=6. \r<BR>\n" );
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document.write( "This means that the equation is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-%28-5%29%29%5E2%2B%28y-1%29%5E2=6%5E2 ALIGN=MIDDLE  ALT=\"%28x-%28-5%29%29%5E2%2B%28y-1%29%5E2=6%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > which simplifies to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%2B5%29%5E2%2B%28y-1%29%5E2=36 ALIGN=MIDDLE  ALT=\"%28x%2B5%29%5E2%2B%28y-1%29%5E2=36\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Since we're dealing with a circle, there are an infinite number of lines of symmetry (ie you can fold the circle in half along any line as long as that line goes through the center). If you're looking for the vertical and horizontal lines of symmetry, then they are in the form of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=h ALIGN=MIDDLE  ALT=\"x=h\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=k ALIGN=MIDDLE  ALT=\"y=k\"   DISABLED_style= \"max-width:90%; height:auto;\" >. So the vertical line of symmetry is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=-5 ALIGN=MIDDLE  ALT=\"x=-5\"   DISABLED_style= \"max-width:90%; height:auto;\" > and the horizontal line of symmetry is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=1 ALIGN=MIDDLE  ALT=\"y=1\"   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
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