document.write( "Question 143992: Solve the equation \"log%2816%2C%28x%29%29%2Blog%288%2C%28x%29%29%2Blog%284%2C%28x%29%29%2Blog%282%2C%28x%29%29=6\" \n" ); document.write( "
Algebra.Com's Answer #104805 by jim_thompson5910(35256)\"\" \"About 
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\"log%2816%2C%28x%29%29%2Blog%288%2C%28x%29%29%2Blog%284%2C%28x%29%29%2Blog%282%2C%28x%29%29=6\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( " Use the change of base formula to rewrite each individual log. Remeber the change of base formula is \"log%28b%2C%28x%29%29=log%2810%2C%28x%29%29%2Flog%2810%2C%28b%29%29\"\r
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\n" ); document.write( "\n" ); document.write( " Rewrite 16 as \"2%5E4\". Rewrite 8 as \"2%5E3\". Rewrite 4 as \"2%5E2\"\r
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\n" ); document.write( "\n" ); document.write( " Rewrite the each denominator using the identity \"log%28b%2C%28x%5Ey%29%29=y%2Alog%28b%2C%28x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( " Multiply both sides by the LCD \"24%2Alog%2810%2C%282%29%29\". Doing this will eliminate the denominators.\r
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\n" ); document.write( "\n" ); document.write( " Distribute and multiply\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%28x%29%29%286%2B8%2B12%2B24%29=144%2Alog%2810%2C%282%29%29\" Factor out the GCF \"log%2810%2C%28x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%28x%29%29%2850%29=144%2Alog%2810%2C%282%29%29\" Add\r
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\n" ); document.write( "\n" ); document.write( "\"50%2Alog%2810%2C%28x%29%29=144%2Alog%2810%2C%282%29%29\" Rearrange the terms\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%28x%5E50%29%29=log%2810%2C%282%5E144%29%29\" Rewrite the expressions using the identity \"y%2Alog%28b%2C%28x%29%29=log%28b%2C%28x%5Ey%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E50=2%5E144\" Since the logs have the same base, this means that the argument (the terms inside the log) are equal.\r
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\n" ); document.write( "\n" ); document.write( "\"x=root%2850%2C2%5E144%29\" Take the 50th root of both sides\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"x=root%2850%2C2%5E144%29\" which is approximately \"x=7.361501\"\r
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\n" ); document.write( "\n" ); document.write( "note: \"x=root%2850%2C2%5E144%29\" can be written as \"x=root%2850%2C2%5E144%29\" =
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