document.write( "Question 143986: How would I solve the below problem...THX tutors!!! :)\r
\n" ); document.write( "\n" ); document.write( "log(16)X + log(8)X + log(4)X + log(2)X = 6\r
\n" ); document.write( "\n" ); document.write( "(the 16, 8, 4, and 2 are all smaller numbers)
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #104801 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
How would I solve the below problem...THX tutors!!! :)
\n" ); document.write( "\"log%2816%2Cx%29+%2B+log%288%2Cx%29+%2B+log%284%2Cx%29+%2B+log%282%2Cx%29+=+6\"
\n" ); document.write( "
\r\n" );
document.write( "Use the 'change of base' formula:\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "on each of the first three terms on the left, using \"2\" as the \"NEW_BASE\"\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( " \r\n" );
document.write( "Now we can evaluate those three denominators by using the definition of\r\n" );
document.write( "logarithm:\r\n" );
document.write( "\r\n" );
document.write( "   \"log%28B%2CA%29=C\" is equivalent to \"B%5EC=A\"\r\n" );
document.write( "\r\n" );
document.write( "For \"log%282%2C16%29\", we set it equal to the unknown \"y\":\r\n" );
document.write( "\r\n" );
document.write( "\"log%282%2C16%29=y\"\r\n" );
document.write( "\r\n" );
document.write( "Then it is equivalent to \"2%5Ey=16\" or \"2%5Ey=2%5E4\", so \"y+=+4\",\r\n" );
document.write( "therefore \"log%282%2C16%29=y=4\"  \r\n" );
document.write( "\r\n" );
document.write( "------\r\n" );
document.write( "\r\n" );
document.write( "For \"log%282%2C8%29\", we set it equal to the unknown \"z\":\r\n" );
document.write( "\r\n" );
document.write( "\"log%282%2C8%29=z\"\r\n" );
document.write( "\r\n" );
document.write( "Then it is equivalent to \"2%5Ez=8\" or \"2%5Ez=2%5E3\", so \"z+=+3\",\r\n" );
document.write( "therefore \"log%282%2C8%29=z=4\" \r\n" );
document.write( "\r\n" );
document.write( "------\r\n" );
document.write( "\r\n" );
document.write( "For \"log%282%2C4%29\", we set it equal to the unknown \"w\":\r\n" );
document.write( "\r\n" );
document.write( "\"log%282%2C4%29=w\"\r\n" );
document.write( "\r\n" );
document.write( "Then it is equivalent to \"2%5Ew=4\" or \"2%5Ew=2%5E2\", so \"w+=+2\",\r\n" );
document.write( "therefore \"log%282%2C4%29=w=2\" \r\n" );
document.write( "\r\n" );
document.write( "------\r\n" );
document.write( "\r\n" );
document.write( "Substitute these for the first three terms of:\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\"log%282%2Cx%29%2F4+%2B+log%282%2Cx%29%2F3+%2B+log%282%2Cx%29%2F2+%2B+log%282%2Cx%29+=+6\"\r\n" );
document.write( "\r\n" );
document.write( "Clear of fractions by multiplying every term by LCD = 12\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\"3log%282%2Cx%29+%2B+4log%282%2Cx%29+%2B+6log%282%2Cx%29+%2B+12log%282%2Cx%29+=+12%2A6\"\r\n" );
document.write( "\r\n" );
document.write( "\"%283%2B4%2B6%2B12%29log%282%2Cx%29+=+72\"\r\n" );
document.write( "\r\n" );
document.write( "\"25%2Alog%282%2Cx%29+=+72\"\r\n" );
document.write( "\r\n" );
document.write( "Divide both sides by 25\r\n" );
document.write( "\r\n" );
document.write( "\"25%2Alog%282%2Cx%29%2F25+=+72%2F25\"\r\n" );
document.write( "\r\n" );
document.write( "\"log%282%2Cx%29+=+72%2F25\"\r\n" );
document.write( "\r\n" );
document.write( "Now use the definition of logarithm again to rewrite\r\n" );
document.write( "that as\r\n" );
document.write( "\r\n" );
document.write( "\"drawing%2850%2C50%2C0%2C2%2C-3%2C2%2C+locate%280%2C0%2Cx=2%5E%2872%2F25%29%29+%29\"\r\n" );
document.write( "\r\n" );
document.write( "Find that on a TI calculator by typing \r\n" );
document.write( "\r\n" );
document.write( "2^(72/25)\r\n" );
document.write( "\r\n" );
document.write( "then pressing ENTER\r\n" );
document.write( "\r\n" );
document.write( "\"x+=+7.361501205\"  \r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" ); document.write( "
\n" );