document.write( "Question 143989: solve for x\r
\n" ); document.write( "\n" ); document.write( "log5(4x)=log5 28\r
\n" ); document.write( "\n" ); document.write( "2log x+ log3= log48\r
\n" ); document.write( "\n" ); document.write( "2^2x+3 = 2^x-5\r
\n" ); document.write( "\n" ); document.write( "4^x= 28
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Algebra.Com's Answer #104799 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'll do the first two to get you started\r
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\n" ); document.write( "\n" ); document.write( "# 1\r
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\n" ); document.write( "\n" ); document.write( "\"log%285%2C%284x%29%29=log%285%2C%2828%29%29\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"4x=28\" Since the logs have the same base, this means that the arguments (the stuff inside the logs) are equal.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2828%29%2F%284%29\" Divide both sides by 4 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=7\" Divide\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So our answer is \"x=7\" \r
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\n" ); document.write( "\n" ); document.write( "# 2\r
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\n" ); document.write( "\n" ); document.write( "\"2log%2810%2C%28x%29%29%2B+log%2810%2C%283%29%29=log%2810%2C%2848%29%29+\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%28x%5E2%29%29%2B+log%2810%2C%283%29%29=log%2810%2C%2848%29%29+\" Rewrite \"2log%2810%2C%28x%29%29\" as \"log%2810%2C%28x%5E2%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%28x%5E2%2A3%29%29=log%2810%2C%2848%29%29+\" Combine the logs using the identity \"log%28b%2C%28A%29%29%2Blog%28b%2C%28B%29%29=log%28b%2C%28A%2AB%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%283x%5E2%29%29=log%2810%2C%2848%29%29+\" Rearrange the terms\r
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\n" ); document.write( "\n" ); document.write( "\"3x%5E2=48\" Since the logs have the same base, this means that the arguments (the stuff inside the logs) are equal\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=16\" Divide both sides by 3\r
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\n" ); document.write( "\n" ); document.write( "\"x=4\" Take the square root of both sides. Note: discard the negative square root. Remember, you cannot take the log of a negative number.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So our answer is \"x=4\"
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