Algebra.Com's Answer #104770 by nabla(475)![\"\"](\"/images/stars/stars-10.gif\")  
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(x + 3)^2 = 28\r
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document.write( "expand LEFT\r
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document.write( "x^2+6x+9=28\r
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document.write( "shift RIGHT to LEFT\r
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document.write( "x^2+6x-19=0\r
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document.write( "USE QUADRATIC FORMULA\r
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document.write( " | Solved by pluggable solver: SOLVE quadratic equation with variable | \n" );
document.write( "Quadratic equation  (in our case  ) has the following solutons:
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document.write( " For these solutions to exist, the discriminant  should not be a negative number.
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document.write( " First, we need to compute the discriminant :  .
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document.write( " Discriminant d=112 is greater than zero. That means that there are two solutions:  .
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document.write( " Quadratic expression  can be factored:
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document.write( " Again, the answer is: 2.29150262212918, -8.29150262212918.\n" );
document.write( "Here's your graph:
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document.write( "Additionally,
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document.write( "(x + 3)^2 = 28
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document.write( "x+3=+/- sqrt(28)
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document.write( "x=-3+/-sqrt(28)
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document.write( "x=-3+/- 2sqrt(7) \n" );
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