document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=143881>Question 143881</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve by the substitution method.<BR>\n" );
document.write( "3x + 4y = 20<BR>\n" );
document.write( "-6x + y = 32<BR>\n" );
document.write( "Will someone please help me with this one. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #104706 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=104706\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> adding 6x to the 2nd equation __ y=32+6x\r<BR>\n" );
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document.write( "substituting into the 1st equation __ 3x+4(32+6x)=20\r<BR>\n" );
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document.write( "distributing __ 3x+128+24x=20 __ subtracting 128 __ 27x=-108 __ dividing by 27 __ x=-4\r<BR>\n" );
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document.write( "substituting __ y=32+[6(-4)] __ y=32-24 __ y=8 </SPAN>\n" );
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