document.write( "Question 143855: 3x^2-41x=-60 \n" ); document.write( "
Algebra.Com's Answer #104675 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\"3x%5E2-41x=-60\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"3x%5E2-41x%2B60=0\" Add 60 to both sides. \r
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\n" ); document.write( "\n" ); document.write( "\"%28x-12%29%283x-5%29=0\" Factor the left side (note: if you need help with factoring, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "Now set each factor equal to zero:\r
\n" ); document.write( "\n" ); document.write( "\"x-12=0\" or \"3x-5=0\" \r
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\n" ); document.write( "\n" ); document.write( "\"x=12\" or \"x=5%2F3\" Now solve for x in each case\r
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\n" ); document.write( "\n" ); document.write( "So our answers are \r
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\n" ); document.write( "\n" ); document.write( " \"x=12\" or \"x=5%2F3\" \r
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