document.write( "Question 143821: Solve.\r
\n" ); document.write( "\n" ); document.write( "Jeff takes 5 hours longer to build a fence than it takes Bill. When they work together, it takes them 6 hours. How long would it take Bill to do the job alone?
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Algebra.Com's Answer #104668 by checkley77(12844)\"\" \"About 
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THE FORMULA FOR THIS PROBLEM IS THE PRODUCT OF THEIR INDIVIDUAL HOURS DIVIDED BY THE SUM OF THEIR HOURS:
\n" ); document.write( "X(X+5)/(X+X+5)=6
\n" ); document.write( "X^2+5X/(2X+5)=6
\n" ); document.write( "X^2+5X=6(2X+5)
\n" ); document.write( "X^2+5X=12X+30
\n" ); document.write( "X^2+5X-12X-30=0
\n" ); document.write( "X^2-7X-30=0
\n" ); document.write( "(X-10)(X+3)=0
\n" ); document.write( "X-10=0
\n" ); document.write( "X=10 HOURS IS THE ANSWER FOR BILL'S TIME TO BUILD THE FENCE.
\n" ); document.write( "10+5=15 HOURS FOR JEFF TO BUILD THE FENCE.
\n" ); document.write( "PROOF
\n" ); document.write( "10*15/(10+15)=6
\n" ); document.write( "150/25=6
\n" ); document.write( "6=6
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