document.write( "Question 143848: The sum of the squares of three consecutive ODD integers is 875. Find the integers \n" ); document.write( "
Algebra.Com's Answer #104665 by checkley77(12844)\"\" \"About 
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LET X, (X+2), & (X+4) BE THE 3 CONSECUTIVE ODD INTEGERS.
\n" ); document.write( "X^2+(X+2)^2+(X+4)^2=875
\n" ); document.write( "X^2+X^2+4X+4+X^2+8X+16=875
\n" ); document.write( "3X^2+12X+4+16-875=0
\n" ); document.write( "3X^2+12X-855=0
\n" ); document.write( "3(X^2+4X-285)=0
\n" ); document.write( "3(X-15)(X+19)=0
\n" ); document.write( "X-15=0
\n" ); document.write( "X=15 ANSWER FOR THE FIRST INTEGER.
\n" ); document.write( "15=2=17 FOR THE SECOND.
\n" ); document.write( "15+4=19 FOR THE THIRD.
\n" ); document.write( "PROOF:
\n" ); document.write( "15^2+17^2+19^2=875
\n" ); document.write( "225+289+361=875
\n" ); document.write( "875=875 \n" ); document.write( "
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