document.write( "Question 143808: The length of a rectangle is two feet more than four times its width. find the width given the area is 42 feet. \r
\n" ); document.write( "\n" ); document.write( "what i have done:
\n" ); document.write( "42=4(x+2)
\n" ); document.write( "42=4x+8
\n" ); document.write( "0=4x-34
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Algebra.Com's Answer #104662 by oscargut(2103)\"\" \"About 
You can put this solution on YOUR website!
width=x
\n" ); document.write( "length=4x+2\r
\n" ); document.write( "\n" ); document.write( "x(4x+2)=42
\n" ); document.write( "4x^2+2x-42=0
\n" ); document.write( "2x^2+x-21=0\r
\n" ); document.write( "\n" ); document.write( "solutions are 3 and -7/2
\n" ); document.write( "so x=3
\n" ); document.write( "and 4x+2=14\r
\n" ); document.write( "\n" ); document.write( "Answer: width is 3 feets
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