document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=21714>Question 21714</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive odd integers such that two times the sume of the first and the third integer is thirteen more than the product of three and the second number. \r<BR>\n" );
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document.write( "I did it like this, help??????\r<BR>\n" );
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document.write( "2x(x+x+4)=13+(3+x+2)<BR>\n" );
document.write( "12x=help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10466 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10466\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First = x<BR>\n" );
document.write( "Second = x+2<BR>\n" );
document.write( "Third = x+4<BR>\n" );
document.write( "2(x+x+4)=13+3(x+2)<BR>\n" );
document.write( "4x+8=13+3x+6<BR>\n" );
document.write( "4x+8=3x+19<BR>\n" );
document.write( "x=11<BR>\n" );
document.write( "11+2=13<BR>\n" );
document.write( "11+4=15<BR>\n" );
document.write( "Hence, the three consective odds integers are 11, 13, and 15.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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