document.write( "Question 143838: Please help me solve this equation: \r
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document.write( "The length of a rectangular room is 3 feet less than twice its width. Find the dimensions of the room if the perimeter is 54 feet. \n" );
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Algebra.Com's Answer #104658 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! LENGTH=2W+3 \n" ); document.write( "WIDTH=W \n" ); document.write( "2L+2W=PERIMETER \n" ); document.write( "2(2W+3)+2W=54 \n" ); document.write( "4W+6+2W=54 \n" ); document.write( "6W=54-6 \n" ); document.write( "6W=48 \n" ); document.write( "W=48/6 \n" ); document.write( "W=8 IS THE WIDTH. \n" ); document.write( "L=2*8+3=16=3=19 IS THE LENGTH. \n" ); document.write( "PROOF \n" ); document.write( "2*19=2*8=54 \n" ); document.write( "38+16=54 \n" ); document.write( "54=54 \n" ); document.write( " \n" ); document.write( " |